Acids and bases
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Date Shared: 13 August 2022
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Worksheet Instructions:
A solution of potassium hydroxide is placed in a beaker. Universal indicator is added to it.The solution is purple, as shown in the diagram below.Sulfuric acid is slowly added to the beaker until no more colour changes are seen. Explain in detail what happens to the colour of the solution while the sulfuric acid is beingadded to the potassium hydroxide.Link your answer to the concentration of ions and the changing pH of the solution.
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As the _sulfuric_ _acid_ (H2SO4) is added, the KOH is being neutralised until water is formed. When no sulfuric acid (H2SO4) is added, the solution is _purple_ and has pH _13-14_ because there is an excess of OH- ions. While the sulfuric acid (H2SO4) is being added, the solution becomes blue with a pH of _8-10._ There is still an excess of _OH-_ ions, but not as big. When the numbers of _H+_ and OH- ions are _equal,_ the solution is _neutralised,_ _green_ and the pH is 7. As more sulfuric acid (H2SO4) is added, the solution becomes _yellow_ pH of 4-5. There is a small excess of H+ ions but not as big. As more sulfuric acid (H2SO4) is added, the solution becomes _red_ with a pH of 1-2. There is a significant excess of _H+_ ions.
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13 August 2022
crillstone Author